Draw compounds that meet the following characteristics:
a) Chiral four-carbon alcohol C4H10O
b) Chiral carboxylic acid of formula C5H10O2
c) A chiral aldehyde of the formula C3H5ClO
a) We draw a linear chain of four carbons with the -OH group in position 2
b) For the acid to be chiral we need a branched chain, with a chiral center. We draw the main chain of four carbons and in methyl as a radical.
c) Main chain of three carbons with chlorine in position 2, thus obtaining a chiral center.