Draw chiral molecules that meet the following characteristics. Mark each center of chirality with an asterisk.

a) Chloroalkane of formula C5H11Cl

b) Alcohol of the formula C6H14O

a) The formula C5H11Cl has no unsaturations. The isomers will be straight or branched chain alkanes.
For the compound to be chiral it is necessary that it contain a carbon attached to four different substituents.
* Carbon attached to four different substituents (chiral center)
b) Formula C6H14O is saturated (complies with the formula CnH2n+2). It is an alcohol with a carbon chain without double bonds or cycles.
There are four chiral isomers that meet the previous formula, but there are more, which you can post in the stereochemistry forum.