Draw the structure of the following carboxylic acids.

1) Propanoic acid
2) 2-ethylhex-3-enoic acid
3) Cyclohex-3-enecarboxylic acid
4) 3-Hydroxyhex-2-enoic acid
5) Butanedioic acid
6) 3-cyclopentylpropanoic acid
7) But-2-enedioic acid
8) 5-bromo-2-methylpentanoic acid
9) 3-Hydroxycyclohexanecarboxylic acid
10) 2-hydroxy-3-oxohexanoic acid
11) Propanedioic Acid
12) Bromoacetic acid


SOLUTION:

1) Propanoic acid

molecule 01
2) 2-ethylhex-3-enoic acid

molecule 02
3) Cyclohex-3-enecarboxylic acid

molecule 03
4) 3-Hydroxyhex-2-enoic acid

molecule 04
5) Butanedioic acid

molecule 05
6) 3-cyclopentylpropanoic acid

molecule 06

7) But-2-enedioic acid

molecule 07
8) 5-bromo-2-methylpentanoic acid

molecule 08
9) 3-Hydroxycyclohexanecarboxylic acid

molecule 09
10) 2-hydroxy-3-oxohexanoic acid

molecule 10
11) Propanedioic Acid

molecule 11
12) Bromoacetic acid

molecule 12