Draw the formulas of the following compounds:
| 1) 2-Methylhexa-1,5-diene 2) 2,3,4-Trimethylocta-1,4,6-triene 3) 4-tert-Butyl-2-chlorohept-1-ene 4) 3-Ethyl-2,4-dimethylhept-3-ene 5) 3,4-Diisopropyl-2,5-dimethylhex-3-ene 6) Hept-1-ene 7) cis-Oct-3-ene 8) 3-ethylpent-2-ene |
9) trans-1,4-Dibromobut-2-ene 10) 3-Chlorohex-2-ene 11) Buta-1,3-diene 12) Hexa-1,4-diene 13) 5-Methyl-3-propylocta-1,4,6-triene 14) 6-Methyl-6-propylnone-2,4,7-triene 15) 2,3,5-Trimethylocta-1,4-diene 16) 3-Propylhepta-1,5-diene. |
SOLUTION:
1) 2-Methylhexa-1,5-diene
2) 2,3,4-Trimethylocta-1,4,6-triene
3) 4-tert-Butyl-2-chlorohept-1-ene
4) 3-Ethyl-2,4-dimethylhept-3-ene
5) 3,4-Diisopropyl-2,5-dimethylhex-3-ene
6) Hept-1-ene
7) cis-Oct-3-ene
8) 3-ethylpent-2-ene 
The cis notation indicates that the equal groups (hydrogens) of the 3,4 positions are oriented to the same side of the alkene.
9) trans-1,4-Dibromobut-2-ene
10) 3-Chlorohex-2-ene
The trans notation indicates that the equal groups of the double bond (hydrogens) are oriented to opposite sides.
11) Buta-1,3-diene
12) Hexa-1,4-diene
13) 5-Methyl-3-propylocta-1,4,6-triene
14) 6-Methyl-6-propylnone-2,4,7-triene
15) 2,3,5-Trimethylocta-1,4-diene
16) 3-Propylhepta-1,5-diene. 
