Draw compounds that meet the following characteristics:
a) Chiral four-carbon alcohol C 4 H 10 O
b) A chiral carboxylic acid of the formula C 5 H 10 O 2
c) A chiral aldehyde of the formula C 3 H 5 ClO
a) We draw a linear chain of four carbons with the -OH group in position 2
b) For the acid to be chiral we need a branched chain, with a chiral center. We draw the main chain of four carbons and in methyl as a radical.
c) Main chain of three carbons with chlorine in position 2, thus obtaining a chiral center.