Draw compounds that meet the following characteristics:

a) Chiral four-carbon alcohol C 4 H ₁₀ O

b) A chiral carboxylic acid of the formula C ₅ H ₁₀ O ₂
c) A chiral aldehyde of the formula C ₃ H ₅ ClO

a) We draw a linear chain of four carbons with the -OH group in position 2

 

 

b) For the acid to be chiral we need a branched chain, with a chiral center. We draw the main chain of four carbons and in methyl as a radical.

 

 

c) Main chain of three carbons with chlorine in position 2, thus obtaining a chiral center.