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Reagents needed 7 years 10 months before #9093

Hello "organic". I have a question about the reagents that should be used to make the transformation that I attach below.



The first reagent I see is potassium permanganate to oxidize the aldehyde group to carboxylic acid and not alter the alcohol. But then, I don't see how to remove the water to close the ring.

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Re: Necessary reagents 7 years 10 months before #9095

Hi, the aldehyde can be oxidized to carboxylic acid in the presence of the alcohol with bromine in water.

You can also use Fehling's reagent (copper sulfate in basic solution). The permanganate for its part will also oxidize the alcohol. The second stage is an acid-catalyzed Fischer esterification between the acid and the alcohol.

www.quimicaorganica.org/acidos-carboxili...sis-de-lactones.html
The following user said thanks: lukilgm

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Re: Necessary reagents 7 years 10 months before #9096

I don't understand stage 3 and stage 4 of the link you gave me.

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Re: Necessary reagents 7 years 10 months before #9097

Stage 3 involves the loss of a proton from the oxygen that belonged to the alcohol and the protonation of one of the hydroxyls to transform it into a good leaving group (water). Stage 4

involves the elimination of the water molecule, aided by the transfer of the pair hydroxyl free.
The following user said thanks: lukilgm

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Re: Necessary reagents 7 years 10 months before #9098

In stage 3: How does the proton lose oxygen from the alcohol and then become protonated to the hydroxyl (which then forms water)?

To what extent does it depend on the medium being acidic/basic/neutral for the equilibrium to shift to one of the sides? In stage 4: Why does the hydroxyl lone pair move to form the double bond? (it is that since it does not have any reagent and it does not indicate the medium in which it is found, I do not understand why there is an elimination) To what extent does it depend on the medium being acidic/basic/neutral for it to move to one of the sides of the balance?

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Re: Necessary reagents 7 years 10 months before #9104

Hello, the esterification reaction is carried out in an acid medium (catalytic sulfuric).

In this acid medium, the basic atoms (oxygen) are continuously protonated and depotated. When the mechanism is written, the appropriate acid-base balances are drawn. Thus, to remove a hydroxyl group we protonate it to transform it into a good leaving group. Acid derivatives always follow a reaction mechanism called addition-elimination.

In a first stage, they add the nucleophile (after protonation if the medium is acid), to later eliminate a group, a stage favored by the strong steric congestion that carbon presents. Greetings
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