ISSUE:

Good morning,

I can't solve it.

If someone could help me? Thanks in advance. The problem is that I have two products of a reaction: - acetic acid
- another acid with a molecular weight of 102.

It is known that the starting compound (C) is a ketone, which is not a methyl ketone, and that it gives the products by energetic oxidation .

It is requested to determine the formula of C.

I've been with this for days and I can't solve it, please if someone knows and can, I would appreciate it.

Regards, garden

jardon wrote: good morning,

I can not solve it.

If someone could help me? Thanks in advance. The problem is that I have two products of a reaction: - acetic acid
- another acid with a molecular weight of 102.

It is known that the starting compound (C) is a ketone, which is not a methyl ketone, and that it gives the products by energetic oxidation and at high temperatures.

It is requested to determine the formula of C.

I've been with this for days and I can't solve it, please if someone knows and can, I would appreciate it.

Regards, garden

the acid with molecular weight 102 is pentanoic acid (Mw=102.13g/mol), and if it starts from the oxidation of a ketone to give acetic acid and pentanoic acid, I think it could be 2-heptanone.

Hello Foreros,

I agree with the pentanoic acid

but I would say that it is 3-heptanone since the statement says that it is not a methyl ketone.

Greetings