Draw compounds that meet the following characteristics:

a) Chiral four-carbon alcohol C4H₁₀O

b) Chiral carboxylic acid of formula C₅H₁₀O₂
c) A chiral aldehyde of the formula C₃H₅ClO

 

a) We draw a linear chain of four carbons with the -OH group in position 2

 

 

b) For the acid to be chiral we need a branched chain, with a chiral center. We draw the main chain of four carbons and in methyl as a radical.

 

 

c) Main chain of three carbons with chlorine in position 2, thus obtaining a chiral center.