Draw the formulas of the following compounds:
| a) 2-Methylhexa-1,5-diene b) 2,3,4-Trimethylocta-1,4,6-triene c) 4-tert-Butyl-2-chlorohept-1-ene d) 3-Ethyl-2 ,4-dimethylhept-3-ene e) 3,4-Diisopropyl-2,5-dimethylhex-3-ene f) Hept-1-ene g) cis-Oct-3-ene h) 3-Ethylpent-2-ene |
i) trans-1,4-Dibromobut-2-ene j) 3-Chlorohex-2-ene k) Buta-1,3-diene l) Hexa-1,4-diene m) 5-Methyl-3-propylocta- 1,4,6-triene n) 6-Methyl-6-propylnon-2,4,7-triene o) 2,3,5-Trimethylocta-1,4-diene p) 3-Propylhepta-1,5-diene . |
SOLUTION:
{note}The cis notation indicates that the equal groups (hydrogens) in the 3,4 positions are oriented to the same side of the alkene.{/note} {note}
The trans notation indicates that the equal groups of the double bond (hydrogens ) face opposite sides.{/nota}
