Name the following alcohols using IUPAC rules

alcohol nomenclature problems



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alcohol nomenclature problems 1. Main chain: the longest that contains the -OH (propane)
2. Numbering: gives the -OH the lowest locant.
3. Substituents: no
4. Name: Propan- 1 - ol


1. Main chain: the longest that contains the -OH (propane)
2. Numbering: does not matter.
3. Substituents: no
4. Name: Propan- 2 - ol



1. Main chain: the longest that contains the -OH (pentane)
2. Numbering: gives the -OH the lowest locant ( -OH preferred over chains)
3. Substituents: 4-methyl
4. Name: 4 - Methyl pentan 2 - ol


1. Main chain: longest (butane)
2. Numbering: starts at one end.
3. Substituents : no
4. Name: Butane- 2,3 - diol


1. Main chain: longest length (hexane)
2. Numbering: starts at the far right, giving -OH the lowest locant.
3. Substituents: bromo in position 4 and methyl in 5 .
4. Name: 4 - Bromo - 5 - methyl hexan- 2 - ol



1. Main chain: longest (heptane)
2. Numbering: starts at the end that gives the lowest locant to -OH .
3. Substituents: 6 -bromo and 5 .
4. Name: 6 - Bromo - 5 - chloro hept- 3 - ol




1. Main chain: six-membered ring (cyclohexane)
2. Numbering: starts at the -OH .
3. Substituents: 3 -methyl .
4. Name: 3 - Methyl cyclohexanol



1. When there is more than one -OH group in a molecule, the quantity prefixes di, tri, tetra, penta, hexa, can be used.... The numbering must give the minor localizers to -OH.
2. The name of the alcohol is built starting with the substituents, preceded by their respective locants, ending with the name of the main chain.
The ending -o of the corresponding alkane is replaced by -ol. 3. In the case of cyclic alcohols it is not necessary to indicate the position of the hydroxyl group, since it always takes locant 1.